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A particular process has 2 independent sources of variation. The standard deviation of the 1st source is 3 units & the standard deviation for the 2nd source is 4 units. The standard deviation of the process is:
Correct Answer: C
Standard deviation of the first source is 3 units and the standard deviation for the second source is 4 units. So, the standard Variance for first source = 9 (= SD^2 = 3 x 3) and Variance for second source is 16.Total Variance of the combined process = 9 + 16 = 25 Standard Deviation of the process = sqrt(Variance) = sqrt(25) = 5 Note: You can only sum up the variances and not Std. deviations.