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Question 71/78
Assuming that you had only one crane capable of 30 lifts per day, 3 column pours requiring 28 lifts each, plus associated assorted work requiring an additional 150 lifts, what is the minimum planned working duration for this work?
Correct Answer: B
Calculation of Total Lifts Required:
* 3 column pours = 28×3=8428 \times 3 = 8428×3=84.
* Additional lifts = 150150150.
* Total lifts = 84+150=23484 + 150 = 23484+150=234.
Lifts Per Day with One Crane:
* 1 crane performs 30 lifts per day.
Required Duration:
* Minimum planned working duration = #234÷30#=18\lceil 234 \div 30 \rceil = 18#234÷30#=18.
Verification with PSP Guidelines:Aligning workload with equipment capacity ensures practical schedule planning (Ref: PSP Study Guide, Chapter 2B: Workload Balancing).
* 3 column pours = 28×3=8428 \times 3 = 8428×3=84.
* Additional lifts = 150150150.
* Total lifts = 84+150=23484 + 150 = 23484+150=234.
Lifts Per Day with One Crane:
* 1 crane performs 30 lifts per day.
Required Duration:
* Minimum planned working duration = #234÷30#=18\lceil 234 \div 30 \rceil = 18#234÷30#=18.
Verification with PSP Guidelines:Aligning workload with equipment capacity ensures practical schedule planning (Ref: PSP Study Guide, Chapter 2B: Workload Balancing).
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