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If the probability of two cars starting on a cold morning is 0.6 for each car. what is the probability of at least one of the cars starting?
Correct Answer: D
To find the probability of at least one car starting on a cold morning, we can use the complement rule. * Determine the probability of one car not starting: * Probability of a car starting: P(start)=0.6P(\text{start}) = 0.6P(start)=0.6 * Probability of a car not starting: P(not start)=10.6=0.4P(\text{not start}) = 1 - 0.6 = 0.4P(not start)=10.6=0.4 * Determine the probability of neither car starting: * Since the cars are independent, the probability of both cars not starting is: P(both not start)=0.4×0.4=0.16P(\text{both not start}) = 0.4 \times 0.4 = 0.16P(both not start)=0.4×0.4=0.16 * Determine the probability of at least one car starting: * P(at least one starts)=1P(both not start)=10.16=0.84P(\text{at least one starts}) = 1 - P(\text{both not start}) = 1 - 0.16 = 0.84P(at least one starts)=1P(both not start)=10.16=0.84 References: Basic principles of probability and complement rule from standard probability texts.