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What happens if you try to compile and run this program? #include <stdio.h> int main (int argc, char *argv[]) { int i = 2; int d= i << 2; d /= 2; printf ("%d", d) ; return 0; } Choose the right answer:
Correct Answer: B
The program outputs 4 because the expression i << 2 performs a left shift operation on the binary representation of i, which is 00000010, by two bits, resulting in 00001000, which is equivalent to 8 in decimal. Then, the expression d /= 2 performs a division assignment operation, which divides d by 2 and assigns the result back to d, resulting in 4. The printf function then prints the value of d as a decimal integer using the %d format specifier. References = CLA - C Certified Associate Programmer Certification, [C Essentials 2 - (Intermediate)], C Bitwise Operators, C Assignment Operators
