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What happens if you try to compile and run this program? #define ALPHA 0 #define BETA ALPHA-1 #define GAMMA 1 #define dELTA ALPHA-BETA-GAMMA #include <stdio.h> int main(int argc, char *argv[]) { printf ("%d", DELTA); return 0; Choose the right answer:
Correct Answer: D
Let's analyze the macros and the program: 1.ALPHA is defined as 0. 2.BETA is defined as ALPHA - 1, which is 0 - 1. 3.GAMMA is defined as 1. 4.DELTA is defined as ALPHA - BETA - GAMMA. With the previous definitions, this expands to 0 - (0 - 1) - 1. Now, let's expand DELTA with the given values: makefileCopy code DELTA = 0 - (0 - 1) - 1 DELTA = 0 - 0 + 1 - 1 DELTA = 0 + 1 - 1 DELTA = 1 - 1 DELTA = 0 It is important to note that the macro dELTA is defined with a lowercase 'd', but the printf function is trying to print DELTA with an uppercase 'D'. Preprocessor tokens are case-sensitive, so this is a mismatch. However, for the sake of the question, let's assume that dELTA was meant to be DELTA with an uppercase 'D'. Since the actual calculation results in 0, but there is a typo in the printf statement (it should print dELTA, not DELTA), the compilation will fail due to DELTA not being defined.
