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What happens if you try to compile and run this program? #include <stdio.h> int main (int argc, char *argv[]) { char *p = "John" " " "Bean"; printf("[%s]", p) ; return 0; } Choose the right answer:
Correct Answer: C
The string literal "John" " " "Bean" is effectively concatenated into a single string by the compiler during compilation. Therefore, the value of p becomes a pointer to the string "John Bean". The printf statement then prints the string enclosed within square brackets, resulting in the output [John Bean].
