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What happens if you try to compile and run this program? #include <stdio.h> int main (int argc, char *argv[]) { char *s = "\\\"\\\\"; printf ("[%c]", s [1]); return 0; } Choose the right answer:
Correct Answer: A
In the program, the character array char *s = "\\\"\\\\"; is defined with the value "\"\\". When printing s[1] using printf("[%c]", s[1]);, it prints the character at index 1 of the string. Here's the breakdown of the string \\\"\\\\: *s[0] is '\' *s[1] is '"' So, the program outputs ["]. Therefore, the correct answer is B. The program outputs ["]
