Valid CLA-11-03 Dumps shared by ExamDiscuss.com for Helping Passing CLA-11-03 Exam! ExamDiscuss.com now offer the newest CLA-11-03 exam dumps, the ExamDiscuss.com CLA-11-03 exam questions have been updated and answers have been corrected get the newest ExamDiscuss.com CLA-11-03 dumps with Test Engine here:
What happens if you try to compile and run this program? #include <stdio.h> int main (int argc, char *argv[]) { char *t = "abcdefgh"; char *p = t + 2; int i; p++; p++; printf("%d ", p[2] - p[-1]); return 0; } Choose the right answer:
Correct Answer: A
The program outputs 3 because the expression p[2] - p[-1] evaluates to 3 using the pointer arithmetic rules in C: The pointer t points to the first element of the string literal "abcdefgh", which is stored in a read-only memory location. The pointer p is initialized to t + 2, which means it points to the third element of the string, which is 'c'. Then, p is incremented twice, so it points to the fifth ele-ment of the string, which is 'e'. The subscript operator [] is equivalent to adding an offset to the pointer and dereferencing it, so p[2] is the same as *(p + 2), which is 'g', and p[-1] is the same as *(p - 1), which is 'd'. The printf function then prints the difference between the ASCII values of 'g' and 'd', which is 103 - 100 = 3, as a decimal integer using the %d format specifier. References = CLA - C Certified Associate Programmer Certification, C Essentials 2 - (Intermediate), C Pointers, C Strings
