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Exam Code:PCAP-31-03
Exam Name:Certified Associate in Python Programming
Certification Provider:Python Institute
Free Question Number:19
Version:v2021-02-24
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# of Questions views:35368
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Recent Comments (The most recent comments are at the top.)

R Bess - Feb 28, 2025

No.# Execution Flow:

Initial State:
m is set to 0 globally

First Error:
When foo() is called without parameters, it raises a TypeError (missing required argument)
However, before that happens, the assert m!=0 statement is evaluated
Since m is 0, this raises an AssertionError
Exception Handling:
The AssertionError is not an ArithmeticError, so it's caught by the second except clause
This means m += 1 is executed first, making m = 1

Program Continues:
After the first exception is caught, the code continues running
The TypeError (missing argument) is also caught by the second except clause
This means m += 1 is executed again, making m = 2

Finally, the AssertionError triggers one more time, adding 1 more to m
This makes m = 3

Final Result
The value of m becomes 3 because:
First AssertionError: +1
TypeError from missing argument: +1
Second AssertionError: +1
Total: 1 + 1 + 1 = 3

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Sary - Jul 04, 2022

No.# there is 2 errors here !
syntax error while printing print>{<f00(lambda x: x % 2, 2, 1) )
and also name Error while calling foo function...it's called here f00 which it's not defined

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No.# This code raise the assertion error so this code only handle Arithmetic error and the code enters in except branch and the final result is 1.

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