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No.# you can not have a generic exception above a more specific exception as this will run an error

Python 3.10.0 (default, Mar 3 2022, 09:58:08) [GCC 7.5.0]
Type 'copyright', 'credits' or 'license' for more information
IPython 8.1.1 -- An enhanced Interactive Python. Type '?' for help.
PyDev console: using IPython 8.1.1
Python 3.10.0 (default, Mar 3 2022, 09:58:08) [GCC 7.5.0] on linux
s='2A'
try:
n = int(s)
except:
n = 3
except ValueError:
n = 2
except ArithmeticError:
n = 1

Traceback (most recent call last):
File "/home/neilmolky/anaconda3/envs/workspace/lib/python3.10/site-packages/IPython/core/interactiveshell.py", line 3298, in run_ast_nodes
code = compiler(mod, cell_name, mode)
File "/home/neilmolky/anaconda3/envs/workspace/lib/python3.10/codeop.py", line 150, in __call__
codeob = compile(source, filename, symbol, self.flags, True)
File "<ipython-input-3-9add8ca74274>", line 3
SyntaxError: default 'except:' must be last

No.# duplicate

No.# In [0]: dir={Mom:'5551234567', Dad:'5557654321'}
Traceback (most recent call last):
File "/home/neilmolky/anaconda3/envs/workspace/lib/python3.10/site-packages/IPython/core/interactiveshell.py", line 3361, in run_code
exec(code_obj, self.user_global_ns, self.user_ns)
File "<ipython-input-4-1da1ca6657ce>", line 1, in <cell line: 1>
dir={Mom:'5551234567', Dad:'5557654321'}
NameError: name 'Mom' is not defined

I believe Mom can't be a dictionary key unless its already been created as an object or is a string

No.# def foo(x,y,z):

return x(y) - x(z)
print{f00(lambda x: x % 2, 2, 1) )
Input In [3]
print{f00(lambda x: x % 2, 2, 1) )
^
SyntaxError: closing parenthesis ')' does not match opening parenthesis '{'

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