The correct answer is D. When running within a Snowflake Native App, the Snowflake Connector for Python automatically uses the current session context, eliminating the need for explicit connection parameters. The code will execute successfully provided that the 'app_public' role has the appropriate privileges, which includes 'SELECT on 'my_table' and 'USAGE on the schema containing the table. Option A is partially correct, but option D provides more specific privilege requirements. Option B is incorrect because explicit connections aren't needed. Option C is incorrect because 'OWNERSHIP' isn't required, only 'SELECT. Option E is incorrect; using 'snowflake.snowpark' may offer performance benefits for data processing, but using "snowflake.connectofl is viable for simple queries.