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Question 51/75

developer created this Apex trigger that calls MyClass .myStaticMethod:
trigger myTrigger on Contact(before insert) ( MyClass.myStaticMethod(trigger.new, trigger.oldMap); } The developer creates a test class with a test method that calls MyClass.mystaticMethod, resulting in 81% overall code coverage. What happens when the developer tries to deploy the trigger and two classes to production, assuming no other code exist?

A. The deployment fails because no assertions were made in the test method.

B. The deployment passes because both classes and the trigger were included in the deployment.

C. The deployment fails because the Apex trigger has no code coverage.

D. The deployment passes because the Apex code has required (>75%) code coverage.

Recent Comments (The most recent comments are at the top.)

claudia - Jun 11, 2022

Is true The Apex Trigger before insert code is not covered in testing but we already got 81 % coverage. So I think the ans is D - Deployment will be ok.

Ran - Apr 26, 2022

My first answer is D. But reading back, " The developer creates a test class with a test method that calls MyClass.mystaticMethod", this assumes that the test class bypasses trigger instead directly calls helper class from test class.

Question 51/75

Recent Comments (The most recent comments are at the top.)

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