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Question 24/56
Refer to the expression below:
Let x = ('1' + 2) == (6 * 2);
How should this expression be modified to ensure that evaluates to false?
Let x = ('1' + 2) == (6 * 2);
How should this expression be modified to ensure that evaluates to false?
Recent Comments (The most recent comments are at the top.)
B.Let x = ('1' + ' 2') == ( 6 * 2);
For B: Let x = ('1' + ' 2') == ( 6 * 2); =====> '1 2' == 12
there is a space between 1 and 2 do not forget so the correct answer is B
option D and it should be with 3 ===
Let x = ('1' + 2) === ( 6 * 2);
All of these options are true
Correct: B
B is Correct
D variant evaluates to true