________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge To schedule a function for later execution in JavaScript, the standard built-in method is:
setTimeout(functionReference, delayInMilliseconds)
Characteristics of setTimeout():
Executes only once.
Delay is specified in milliseconds.
Requires passing the function reference, not calling the function.
Two minutes is:
2 minutes = 120 seconds = 120,000 milliseconds
Now evaluate each option:
________________________________________
Option A: delay(sayHello, 120000);
Incorrect.
There is no built-in delay() function in JavaScript.
________________________________________
Option B: setTimeout(sayHello, 120000);
Correct.
sayHello is passed as a function reference, so it will execute once after 120,000 ms.
________________________________________
Option C: setTimeout(sayHello(), 120000);
Incorrect.
sayHello() calls the function immediately, and the return value (undefined) is passed to setTimeout.
This executes the function right away instead of after two minutes.
________________________________________
Option D: setInterval(sayHello, 120000);
Incorrect.
setInterval() repeats execution every 120,000 ms.
The question requires executing the function once, so this cannot be correct.
________________________________________
JavaScript Knowledge Reference (text-only)
setTimeout() schedules a function to run once after a specified delay.
Passing functionName gives a reference; passing functionName() invokes it immediately.
setInterval() repeats indefinitely, unlike setTimeout().