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- Question 27
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Question 27/68
Given the code below:
01 function Person() {
02 this.firstName = 'John';
03 }
04
05 Person.proto = {
06 job: x => 'Developer'
07 });
08
09 const myFather = new Person();
10 const result = myFather.firstName + ' ' + myFather.job();
What is the value of result when line 10 executes?
01 function Person() {
02 this.firstName = 'John';
03 }
04
05 Person.proto = {
06 job: x => 'Developer'
07 });
08
09 const myFather = new Person();
10 const result = myFather.firstName + ' ' + myFather.job();
What is the value of result when line 10 executes?
Correct Answer: A
Person.proto is being set, but JavaScript uses Person.prototype for the prototype chain, not Person.proto.
Therefore, job is not on Person.prototype, and instances of Person do not have job via prototype.
myFather is created with new Person(), so:
myFather.firstName is 'John'.
myFather.job is undefined.
Attempting to call myFather.job() results in:
TypeError: myFather.job is not a function
So option A is correct.
________________________________________
Therefore, job is not on Person.prototype, and instances of Person do not have job via prototype.
myFather is created with new Person(), so:
myFather.firstName is 'John'.
myFather.job is undefined.
Attempting to call myFather.job() results in:
TypeError: myFather.job is not a function
So option A is correct.
________________________________________
- Question List (68q)
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