Comprehensive and Detailed In-Depth Explanation:
Understanding the BGP Network Topology in the Question:
* EBGP Peering
* Each router forms EBGP peer relationships with directly connected neighbors.
* This is a fully meshed topology, meaning each router exchanges BGP routes with its adjacent routers.
* Routing Information for 192.168.1.0/24
* R1 and R4 import the static route 192.168.1.0/24 into BGP.
* Since BGP prefers the shortest AS path, traffic to 192.168.1.0/24 will follow the shortest path to R1 or R4.
Route Analysis for Each Statement:
Statement A: R6 # R5 # R4 # (Correct)
* R6 does not have a direct route to 192.168.1.0/24, so it must rely on BGP advertisements from its EBGP neighbors.
* R5 learns the route to 192.168.1.0/24 from R4.
* Therefore, R6 forwards traffic to R5, and then R5 sends it to R4.
# Correct path: R6 # R5 # R4
Statement B: R5 # R4 # (Correct)
* R5 is directly connected to R4, and since R4 advertises the 192.168.1.0/24 route via BGP,
* R5 will forward traffic directly to R4 as the shortest AS path.
# Correct path: R5 # R4
Statement C: R2 # R1 # (Correct)
* R2 is directly connected to R1 and learns the 192.168.1.0/24 route from R1 via BGP.
* Since R1 advertises the static route, R2 forwards traffic directly to R1.
# Correct path: R2 # R1
Statement D: R3 # R2 # R1 # (Correct)
* R3 is directly connected to R2 and learns the 192.168.1.0/24 route from R2 via BGP.
* Since R2 prefers R1 as the shortest AS path to 192.168.1.0/24,
* R3 will send traffic to R2, and R2 will send it to R1.
# Correct path: R3 # R2 # R1
Final Conclusion:
# A. The path for traffic from R6 to 192.168.1.0/24 is R6 # R5 # R4.# B. The path for traffic from R5 to
192.168.1.0/24 is R5 # R4.# C. The path for traffic from R2 to 192.168.1.0/24 is R2 # R1.# D. The path for traffic from R3 to 192.168.1.0/24 is R3 # R2 # R1.
Thus, the correct answers are: A, B, C, D.