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Which address would successfully summarize only the networks seen?
Correct Answer: C
Explanation/Reference: Explanation: Let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to 192.168.15.255 So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary. In fact just count the number if subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21. If you make it an binary you'll find out the answer too: the interesting octet is 3rd one so let's convert in binary. 8 00001 000 9 00001 001 10 00001 010 11 00001 011 12 00001 100 13 00001 101 14 00001 110 15 00001 111 I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is 192.168.8.0