Explanation
The requirements are to support two host failures, use the least amount of hosts, and maximize user capacity.
RAID 5/6 and RAID 1 are both suitable options for a storage policy that can support two host failures.
However, RAID 5/6 will be more efficient in terms of space utilization, allowing for a larger user capacity. In addition, the use of four hosts instead of five will minimize the number of hosts required, reducing costs associated with hardware and licensing.
According to VMware vSAN Design and sizing guide, the Failure to Tolerate (FTT) policy defines the number of replicas that must be kept for each object. In this case, FTT=2 means that two replicas of each object will be created. FTT=2 provides protection against the failure of two hosts. The Failure to Tolerate for the capacity tier (FFT) policy defines the number of parity fragments that must be kept for each stripe. RAID 5/6 requires FFT=1, which means that one parity fragment will be created for each stripe.
Therefore, the best answer is A. 4 Hosts, FFT=2, RAID 5/6.
https://vmc.techzone.vmware.com/vmc-arch/docs/storage/vmc-aws-vsan-architecture To support two host failures (FTT=2), a minimum of four hosts is required. RAID 5/6 erasure coding can be used to maximize user capacity while using the least amount of hosts. Thisconfiguration will satisfy all three requirements: supporting two host failures, using the least amount of hosts, and maximizing user capacity.