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You have a Snowpark DataFrame 'customer df with a 'customer name' column. You need to create a new column 'initials' that contains the initials of each customer's name. For example, if 'customer name' is 'John Doe', 'initials' should be 'JD'. You must handle names with multiple words correctly. Which Snowpark SQL expression using the "col()' function is the most efficient and correct way to define the 'initials' column?
Correct Answer: D
Option D is the most robust and efficient solution. It uses a regular expression to extract the first letter of each word in the name, handling multiple words correctly, and converting it to uppercase. Option A is incorrect because it only handles two-word names and relies on string concatenation, which can be less efficient than using the 'concat function. Option B is incorrect as 'array_accumulate' is not used in Snowpark to compute initials. Option C is incorrect as it is too basic and relies on two-word names only. Option E is incorrect as it extracts only the first two characters from the name.