JavaScript-Developer-I Exam Dumps | A developer has two ways to write a function: Option A: function Monster(){ this.growl = ()=>{ console.log('Grr!');

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Question 18

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Question 18/110

A developer has two ways to write a function:
Option A:
function Monster(){
this.growl = ()=>{
console.log('Grr!');
}
}
Option B:
function Monster(){};
Monster.prototype.growl = ()=>{
console.log('Grr!');
}
After deciding on an option, the developercreates 1000 monster objects.
How many growl methods are created with Option A and Option B?

A. 1 for Option A, 1000 for Option B

B. 1000 for both

C. 1 methods for both

D. 1000 for Option A, 1 for Option B

Correct Answer: C

Recent Comments (The most recent comments are at the top.)

German - Jan 13, 2025

B ) 1000 for both!
prototype: This ensures the function is defined once and shared by all instances created from this constructor.

Shobhit - Sep 15, 2024

Yes D is correct

Alexander - Aug 22, 2024

I tend to think that D is correct. When you create objects with A, growl method is created for each object. So growl property of one object would be not equal to another although they would look identical

When you create objects with B, the growl method is inherited, so it will be equal to itself on every object

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Question 18/110

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