Tried by executing the code and answer is 11
It runs synchronous lines first and adds async methods like settimeout/setinterval functions in queue even if time is 0... so it will print 11 first and then add in the value

Try on your own aswell:
let total = 10;
const interval = setInterval(()=>{
total++;
clearInterval(interval);
total++;
},0);
total++;
console.log(total);

Should be 12.

The variable total is initialized to 10.
setInterval is called with a callback function that increments total and then immediately clears the interval.
total is incremented once outside of the setInterval.
The console.log(total) statement outputs the value of total.
Here's the breakdown of the execution steps:

Initial value of total: 10
Inside the setInterval callback:
Increment total: 11
Clear the interval
Increment total outside the setInterval: 12
Output the value of total using console.log: 12
The key here is that even though the interval callback is triggered immediately, it does not interrupt the execution of subsequent code. Therefore, the total variable is incremented to 11 inside the interval callback, but then it's immediately cleared. The subsequent increment outside the interval is not affected by the interval callback because it occurs after the interval is cleared.