The correct answer is C, after correcting the option text to match the actual code.
The object is created here:
let student = new GraduateStudent("Jane");
Because GraduateStudent extends Student, its constructor runs:
constructor(name) {
super(name);
this._name = "Graduate Student " + name;
}
The call to:
super(name);
runs the parent Student constructor first and temporarily sets:
this._name = "Jane";
Then this line in the child constructor overwrites that value:
this._name = "Graduate Student " + name;
So the final value of this._name becomes:
"Graduate Student Jane"
Next, this line executes:
student.displayGrade();
Since student is an instance of GraduateStudent, JavaScript uses the overridden displayGrade() method from GraduateStudent, not the parent method from Student.
The executed method is:
displayGrade() {
console.log(`${this._name} got 100% on test.`);
}
Therefore, the console output is:
Graduate Student Jane got 100% on test.
Important correction: the original option C said something like "Better student Jackie got 100% on test.", but the actual code uses "Graduate Student " and the name "Jane". The verified corrected answer remains C.