1Z0-898 Exam Dumps | A developer is writing an application with three java Persistence API entities: order, customer, and

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Question 30/63

A developer is writing an application with three java Persistence API entities: order, customer, and Address. There is a many-to-one relationship between order and customer, and a one to-many relationship between customer and Address.
Which two Criteria queries will return the orders of all customers who have an address whose value specified by the String parameter postalcode? (Choose two)

A. String postalCode = . . .
Criteria Builder cb = . . .
CriteriaQuery<order> cq = cb.createQuery (Order.class);
Root <order> order = cq.from(order.class);
Join <order, Customer> customer = order.join(Order_.customer);
Root <Order> order = cq.from (Order.class);
Join <customer, Address> address = customer join (Order_.customer)
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
.. .

B. String postalCode = . . .
Criteria Builder cb = . . .
Root <Order> order = cq.from (Order.class);
order.join (order_. customer).join(Customer_.addresses);
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here

C. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq.from (Order . class) ,
Join<order, Address> address = order.join(Customer_.addresses);
cq.where(ct>.equal(address.get(Address_.postalCode), postalCode));
cq-select(order).distinct(true);
// query execution code here
.. .

D. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq.from (Order . class ) ,
Join<order, Address> address = order . join (Order_. customer).join (Customer_.addresses); cq.where <cb.equal (address.get(Address_.postalCode) , postalCode) ) ; cq.selec:(order).distinct (true);
// query execution code here
.. .

Question 30/63

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