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Question 62/183
Given:
public class ColorTest {
public static void main(String[] args) {
String[] colors = {"red", "blue","green","yellow","maroon","cyan"};
int count = 0;
for (String c : colors) {
if (count >= 4) {
break;
}
else {
continue;
}
if (c.length() >= 4) {
colors[count] = c.substring(0,3);
}
count++;
}
System.out.println(colors[count]);
}
}
What is the result?
public class ColorTest {
public static void main(String[] args) {
String[] colors = {"red", "blue","green","yellow","maroon","cyan"};
int count = 0;
for (String c : colors) {
if (count >= 4) {
break;
}
else {
continue;
}
if (c.length() >= 4) {
colors[count] = c.substring(0,3);
}
count++;
}
System.out.println(colors[count]);
}
}
What is the result?
Correct Answer: C
The line, if (c.length() >= 4) {, is never reached. This causes a compilation error.
Note: The continue statement skips the current iteration of a for, while , or do-while loop.
An unlabeled break statement terminates the innermost switch, for, while, or do- while statement, but a labeled break terminates an outer statement.
Note: The continue statement skips the current iteration of a for, while , or do-while loop.
An unlabeled break statement terminates the innermost switch, for, while, or do- while statement, but a labeled break terminates an outer statement.
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