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Question 32/55
Given the following Python script:
#1/usr/bin/python
import socket as skt
for port in range (1,1024):
try:
sox=skt.socket(skt.AF.INET,skt.SOCK_STREAM)
sox.settimeout(1000)
sox.connect (('127.0.0.1', port))
print '%d:OPEN' % (port)
sox.close
except: continue
Which of the following is where the output will go?
#1/usr/bin/python
import socket as skt
for port in range (1,1024):
try:
sox=skt.socket(skt.AF.INET,skt.SOCK_STREAM)
sox.settimeout(1000)
sox.connect (('127.0.0.1', port))
print '%d:OPEN' % (port)
sox.close
except: continue
Which of the following is where the output will go?
