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| Exam Code: | 70-741 |
| Exam Name: | Networking with Windows Server 2016 |
| Certification Provider: | Microsoft |
| Free Question Number: | 48 |
| Version: | v2018-05-02 |
| Rating: | |
| # of views: | 1131 |
| # of Questions views: | 21466 |
| Go To 70-741 Questions | |
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No.# I would say the answer is A!
IP: 172.20.10.50 applies to route: 172.16.0.0 / 255.240.0.0
IP: 172.16.0.1
= 1010 1100.0001 0000.0000 0000.0000 0001
NM: 255.240.0.0
= 1111 1111.1111 0000.0000 0000.0000 0000
Here you see the first 12 bits determine the Network ID
NID: 172.16.0.0
IP: 172.20.10.50
= 1010 1100.0001 0100.0000 1010.0011 0010
It has the same first 12 bits as IP: 172.16.0.1
So IP: 172.16.0.1/12 is in the same Network as IP: 172.20.10.50/12
Now I hope to have proven to you that 172.20.10.50 applies to the route 172.16.0.0 / 255.240.0.0
(The last IP in NID:172.16.0.0 with 12 bits: 172.31.255.255/12
IP: 172.31.255.255
= 1010 1100.0001 1111.1111 1111.1111 1111
It has the same first 12 bits as IP: 172.16.0.1
Address range: 172.16.0.1 - 172.31.255.254
)