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The result of the following code is that the record will not be created and an exception will be thrown. This is because the code is trying to insert a record with a null value for a required field, which violates the database constraints and causes a DMLException1. The code does not handle the exception with a try-catch block, so the exception will propagate to the caller and terminate the execution2. The debug log will show the exception message and stack trace, but the record will not be inserted in the database. Java Account a = new Account(); a.Name = null; insert a; AI-generated code. Review and use carefully. More info on FAQ. The other options are incorrect. Option B is incorrect because the record will not be created and the debug log will show an exception, not a message. Option C is incorrect because the record will not be created and an error will be reported as an exception. Option D is incorrect because the record will not be created and an error will be reported as an exception. References: * DMLException Class | Apex Developer Guide | Salesforce Developers * Exception Handling | Apex Developer Guide | Salesforce Developers
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Account a = new Account();
Database.insert(a, false);
C. The record will not be created and no error will be reported. The Answer
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