If AP power level is increased from 25 mW to 100 mW. what is the power difference in dBm?
Correct Answer: C
The power difference in dBm can be calculated using the formula:
10×log10(P1P2)
where (P1) and (P2) are the initial and final power levels in milliwatts (mW). So, for an increase from 25 mW to 100 mW, the calculation is
10×log10(25100)=10×log10(4)=10×0.6=6dBm
However, since the question asks for the difference, we need to consider that dBm is a logarithmic unit, so we use the formula for power ratio in dB which is
10×log10(PowerRatio)
The power ratio here is
25mW100mW=4
Therefore,
10×log10(4)=10×0.6=6dBm
But this is the increase for each doubling of power. Since we are increasing from 25 mW to 100 mW, which is a fourfold increase or two doublings (25 mW to 50 mW to 100 mW), we have two increments of 6 dBm, which gives us a total increase of 12 dBm. However, the closest answer to 12 dBm is 17 dBm, which is answer
C: References: Implementing and Operating Cisco Service Provider Network Core Technologies (SPCOR) training materials