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Suppose you were told that scores on an examination were converted to standard scores with a mean = 500, range of 800, and a standard deviation of 100. A person with a score of 600 has performed better than what percent of the persons taking the test?
Correct Answer: C
Z = (X - MU)/Standard Deviation Z = (600 - 500)/100 = 1 Area between Z and Mean = .3413 Area to Left of Z = .5 + .3413 = .8413 Percentile Rank = 100*.8413 = 84.13 Therefore, the person has performed better than 84 percent of the people.